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- <h3 id="前置知识"><a class="markdownIt-Anchor" href="#前置知识"></a> 前置知识</h3>
- <p>存图方式(<a href="http://baidu.physton.com/?q=%E9%82%BB%E6%8E%A5%E8%A1%A8" target="_blank" rel="noopener" title="简单">邻接表</a>,<a href="http://baidu.physton.com/?q=%E9%82%BB%E6%8E%A5%E7%9F%A9%E9%98%B5" target="_blank" rel="noopener" title="都太简单了,没有一个打得过的">邻接矩阵</a>),<a href="https://schtonn.github.io/2020/03/01/union-find">并查集</a>。<br />
- 不会的快进入链接学习吧!</p>
- <h3 id="引入"><a class="markdownIt-Anchor" href="#引入"></a> 引入</h3>
- <p>生成树,就是从一个图中选中<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mi>n</mi><mo>−</mo><mn>1</mn></mrow><annotation encoding="application/x-tex">n-1</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.66666em;vertical-align:-0.08333em;"></span><span class="mord mathdefault">n</span><span class="mspace" style="margin-right:0.2222222222222222em;"></span><span class="mbin">−</span><span class="mspace" style="margin-right:0.2222222222222222em;"></span></span><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">1</span></span></span></span>条边,使得这些边构成一棵树,并包含图中的所有节点。<br />
- 最小生成树,就是找到一种生成树,使得这个生成树的边权和最小。</p>
- <a id="more"></a>
- <h3 id="生成方式一prim"><a class="markdownIt-Anchor" href="#生成方式一prim"></a> 生成方式一:prim</h3>
- <p>这种方法有点类似<a href="http://baidu.physton.com/?q=dijkstra" target="_blank" rel="noopener" title="这都不会?">Dijstra</a>,就是每次从所有<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mi>v</mi><mi>i</mi><mi>s</mi></mrow><annotation encoding="application/x-tex">vis</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.65952em;vertical-align:0em;"></span><span class="mord mathdefault" style="margin-right:0.03588em;">v</span><span class="mord mathdefault">i</span><span class="mord mathdefault">s</span></span></span></span>过的点遍历能达到的边,从其中选择一条最小的,加入生成树。</p>
- <hr />
- <p>假设我们有这么一张图:<br />
- <a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><img data-src="https://img-blog.csdnimg.cn/20200103203601629.png" alt="" /></a></p>
- <p>就从0号点开始吧:<br />
- <a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><br />
- <img data-src="https://img-blog.csdnimg.cn/20200103204749157.png" alt="在这里插入图片描述" /></a></p>
- <p>找到从<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>0</mn></mrow><annotation encoding="application/x-tex">0</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">0</span></span></span></span>出发的最小的边:<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>0</mn><mo separator="true">,</mo><mn>2</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[0,2]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">0</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">2</span><span class="mclose">]</span></span></span></span>,边权为<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>3</mn></mrow><annotation encoding="application/x-tex">3</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">3</span></span></span></span>,那么对<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>2</mn></mrow><annotation encoding="application/x-tex">2</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">2</span></span></span></span>号点进行标记。<br />
- <a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><img data-src="https://img-blog.csdnimg.cn/20200103205741495.png" alt="" /></a></p>
- <p>然后从<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>0</mn></mrow><annotation encoding="application/x-tex">0</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">0</span></span></span></span>号和<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>2</mn></mrow><annotation encoding="application/x-tex">2</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">2</span></span></span></span>号节点继续找,发现最小的是<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>2</mn><mo separator="true">,</mo><mn>4</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[2,4]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">2</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">4</span><span class="mclose">]</span></span></span></span>边,那么就标记<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>4</mn></mrow><annotation encoding="application/x-tex">4</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">4</span></span></span></span>号节点。<br />
- <a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><img data-src="https://img-blog.csdnimg.cn/20200103210306831.png" alt="在这里插入图片描述" /></a></p>
- <p>然后是<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>4</mn><mo separator="true">,</mo><mn>1</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[4,1]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">4</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">1</span><span class="mclose">]</span></span></span></span>,<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>1</mn></mrow><annotation encoding="application/x-tex">1</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.64444em;vertical-align:0em;"></span><span class="mord">1</span></span></span></span>号。<br />
- <a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><img data-src="https://img-blog.csdnimg.cn/20200103210445854.png" alt="在这里插入图片描述" /></a></p>
- <p>以此类推,最后就生成出来了这样一个图:</p>
- <p><a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><img data-src="https://img-blog.csdnimg.cn/20200103210621487.png" alt="在这里插入图片描述" /></a></p>
- <p>把没有标记的边删掉,就是最小生成树。<br />
- <a href="https://csacademy.com/app/graph_editor" target="_blank" rel="noopener" title="点击查看生成工具"><img data-src="https://img-blog.csdnimg.cn/20200103210727778.png" alt="" /></a></p>
- <p>这就是prim算法 <s>,代码我不会写</s>在后面。</p>
- <h3 id="生成方式二kruskal"><a class="markdownIt-Anchor" href="#生成方式二kruskal"></a> 生成方式二:kruskal</h3>
- <p>这个算法本质上就是把所有边按照边权排序,然后直接<s>爆炸</s>按顺序判断要不要加进生成树里。<br />
- kruskal算法使用了一种极速闪电致命又自杀的东西:并查集。<br />
- <a href="https://schtonn.github.io/post/union-find-set">他有多快呢?</a></p>
- <hr />
- <p>好了我们在建一个图模拟一下吧<br />
- <img data-src="https://img-blog.csdnimg.cn/20200103215213917.png" alt="在这里插入图片描述" /></p>
- <p>先给边排序。最小的是<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>2</mn><mo separator="true">,</mo><mn>3</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[2,3]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">2</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">3</span><span class="mclose">]</span></span></span></span>,把他拿出来,判断一下。怎么判断呢?首先访问一下并查集看一看,这个边连接的两个点在不在同一个集合内,不在的话就把这条边加入生成树,然后把两个点合并。否则忽略这一条变,继续。这一条边符合要求,加进并查集里,现在<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mn>2</mn><mo separator="true">,</mo><mn>3</mn></mrow><annotation encoding="application/x-tex">{2,3}</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.8388800000000001em;vertical-align:-0.19444em;"></span><span class="mord"><span class="mord">2</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">3</span></span></span></span></span>是一个集合,剩下都是独立的。</p>
- <p><img data-src="https://img-blog.csdnimg.cn/20200103215304212.png" alt="在这里插入图片描述" /><br />
- 现在最小的有<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>1</mn><mo separator="true">,</mo><mn>4</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[1,4]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">1</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">4</span><span class="mclose">]</span></span></span></span>和<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>4</mn><mo separator="true">,</mo><mn>5</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[4,5]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">4</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">5</span><span class="mclose">]</span></span></span></span>,我们都判断一下,都可以。<br />
- <img data-src="https://img-blog.csdnimg.cn/20200103215356204.png" alt="在这里插入图片描述" /></p>
- <p>然后就是<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>0</mn><mo separator="true">,</mo><mn>4</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[0,4]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">0</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">4</span><span class="mclose">]</span></span></span></span>和<span class="katex"><span class="katex-mathml"><math><semantics><mrow><mo stretchy="false">[</mo><mn>2</mn><mo separator="true">,</mo><mn>4</mn><mo stretchy="false">]</mo></mrow><annotation encoding="application/x-tex">[2,4]</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mopen">[</span><span class="mord">2</span><span class="mpunct">,</span><span class="mspace" style="margin-right:0.16666666666666666em;"></span><span class="mord">4</span><span class="mclose">]</span></span></span></span>,依然都是可以的。<br />
- <img data-src="https://img-blog.csdnimg.cn/20200103215507942.png" alt="在这里插入图片描述" /><br />
- 这样,一颗活灵活现的生成树就出现了。<br />
- <img data-src="https://img-blog.csdnimg.cn/20200103215600881.png" alt="" /></p>
- <p>好了!</p>
- <h3 id="代码luogup3366"><a class="markdownIt-Anchor" href="#代码luogup3366"></a> 代码(<a href="https://www.luogu.com.cn/problem/P3366" target="_blank" rel="noopener">luoguP3366</a>)</h3>
- <p>kruskal的代码又短又易于理解,甚至可以直接用数组存边,所以他非常好写,推荐。</p>
- <h4 id="prim"><a class="markdownIt-Anchor" href="#prim"></a> prim</h4>
- <figure class="highlight cpp"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br><span class="line">25</span><br><span class="line">26</span><br><span class="line">27</span><br><span class="line">28</span><br><span class="line">29</span><br><span class="line">30</span><br><span class="line">31</span><br><span class="line">32</span><br><span class="line">33</span><br><span class="line">34</span><br><span class="line">35</span><br><span class="line">36</span><br><span class="line">37</span><br><span class="line">38</span><br><span class="line">39</span><br><span class="line">40</span><br><span class="line">41</span><br><span class="line">42</span><br><span class="line">43</span><br><span class="line">44</span><br><span class="line">45</span><br><span class="line">46</span><br><span class="line">47</span><br><span class="line">48</span><br><span class="line">49</span><br><span class="line">50</span><br><span class="line">51</span><br><span class="line">52</span><br><span class="line">53</span><br><span class="line">54</span><br><span class="line">55</span><br><span class="line">56</span><br><span class="line">57</span><br><span class="line">58</span><br><span class="line">59</span><br><span class="line">60</span><br><span class="line">61</span><br><span class="line">62</span><br><span class="line">63</span><br><span class="line">64</span><br><span class="line">65</span><br><span class="line">66</span><br><span class="line">67</span><br></pre></td><td class="code"><pre><span class="line"><span class="meta">#<span class="meta-keyword">include</span> <span class="meta-string">"iostream"</span></span></span><br><span class="line"><span class="meta">#<span class="meta-keyword">include</span> <span class="meta-string">"queue"</span></span></span><br><span class="line"><span class="meta">#<span class="meta-keyword">include</span> <span class="meta-string">"cstring"</span></span></span><br><span class="line"><span class="keyword">using</span> <span class="keyword">namespace</span> <span class="built_in">std</span>;</span><br><span class="line"><span class="meta">#<span class="meta-keyword">define</span> maxm 5000010</span></span><br><span class="line"><span class="meta">#<span class="meta-keyword">define</span> maxn 1000010</span></span><br><span class="line"><span class="meta">#<span class="meta-keyword">define</span> inf 0x3f3f3f3f</span></span><br><span class="line"><span class="keyword">int</span> ans=<span class="number">0</span>;</span><br><span class="line"><span class="class"><span class="keyword">struct</span> <span class="title">node</span>{</span></span><br><span class="line"> <span class="keyword">int</span> v,next,c;</span><br><span class="line">}e[maxm<<<span class="number">1</span>];</span><br><span class="line"><span class="keyword">int</span> h[maxn],tot,n,m;</span><br><span class="line"><span class="function"><span class="keyword">void</span> <span class="title">adde</span><span class="params">(<span class="keyword">int</span> u,<span class="keyword">int</span> v,<span class="keyword">int</span> c)</span></span>{</span><br><span class="line"> tot++;</span><br><span class="line"> e[tot].v=v;</span><br><span class="line"> e[tot].c=c;</span><br><span class="line"> e[tot].next=h[u];</span><br><span class="line"> h[u]=tot;</span><br><span class="line">}</span><br><span class="line"><span class="keyword">int</span> dis[maxn];</span><br><span class="line"><span class="keyword">bool</span> vis[maxn];</span><br><span class="line"><span class="class"><span class="keyword">struct</span> <span class="title">qu</span>{</span></span><br><span class="line"> <span class="keyword">int</span> id,dis;</span><br><span class="line"> <span class="keyword">bool</span> <span class="keyword">operator</span> < (<span class="keyword">const</span> qu t)<span class="keyword">const</span>{</span><br><span class="line"> <span class="keyword">return</span> dis>t.dis;</span><br><span class="line"> }</span><br><span class="line">};</span><br><span class="line">priority_queue<qu> q;</span><br><span class="line"><span class="function"><span class="keyword">void</span> <span class="title">dijk</span><span class="params">(<span class="keyword">int</span> s)</span></span>{</span><br><span class="line"> <span class="built_in">memset</span>(dis,<span class="number">0x3f</span>,<span class="keyword">sizeof</span>(dis));</span><br><span class="line"> <span class="built_in">memset</span>(vis,<span class="number">0</span>,<span class="keyword">sizeof</span>(vis));</span><br><span class="line"> <span class="keyword">while</span>(!q.empty())q.pop();</span><br><span class="line"> qu t;</span><br><span class="line"> t.dis=<span class="number">0</span>;</span><br><span class="line"> t.id=s;</span><br><span class="line"> dis[s]=<span class="number">0</span>;</span><br><span class="line"> q.push(t);</span><br><span class="line"> <span class="keyword">while</span>(!q.empty()){</span><br><span class="line"> t=q.top();q.pop();</span><br><span class="line"> <span class="keyword">if</span>(vis[t.id])<span class="keyword">continue</span>;</span><br><span class="line"> vis[t.id]=<span class="literal">true</span>;</span><br><span class="line"> ans+=t.dis;</span><br><span class="line"> <span class="keyword">for</span>(<span class="keyword">int</span> j=h[t.id];j;j=e[j].next){</span><br><span class="line"> <span class="keyword">int</span> v=e[j].v;</span><br><span class="line"> <span class="keyword">if</span>(!vis[v]&&dis[v]>e[j].c){</span><br><span class="line"> dis[v]=e[j].c;</span><br><span class="line"> qu now;</span><br><span class="line"> now.id=v;</span><br><span class="line"> now.dis=dis[v];</span><br><span class="line"> q.push(now);</span><br><span class="line"> }</span><br><span class="line"> }</span><br><span class="line"> }</span><br><span class="line">}</span><br><span class="line"><span class="function"><span class="keyword">int</span> <span class="title">main</span><span class="params">()</span></span>{</span><br><span class="line"> <span class="keyword">int</span> s=<span class="number">1</span>;</span><br><span class="line"> <span class="built_in">cin</span>>>n>>m;</span><br><span class="line"> <span class="keyword">int</span> u,v,c;</span><br><span class="line"> <span class="keyword">for</span>(<span class="keyword">int</span> i=<span class="number">1</span>;i<=m;i++){</span><br><span class="line"> <span class="built_in">cin</span>>>u>>v>>c;</span><br><span class="line"> adde(u,v,c);</span><br><span class="line">adde(v,u,c);</span><br><span class="line"> }</span><br><span class="line"> dijk(s);</span><br><span class="line"><span class="built_in">cout</span><<ans<<<span class="built_in">endl</span>;</span><br><span class="line"> <span class="keyword">return</span> <span class="number">0</span>;</span><br><span class="line">}</span><br></pre></td></tr></table></figure>
- <h4 id="kruskal"><a class="markdownIt-Anchor" href="#kruskal"></a> kruskal</h4>
- <figure class="highlight cpp"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br><span class="line">25</span><br><span class="line">26</span><br><span class="line">27</span><br><span class="line">28</span><br><span class="line">29</span><br><span class="line">30</span><br><span class="line">31</span><br></pre></td><td class="code"><pre><span class="line"><span class="meta">#<span class="meta-keyword">include</span> <span class="meta-string">"iostream"</span></span></span><br><span class="line"><span class="meta">#<span class="meta-keyword">include</span> <span class="meta-string">"algorithm"</span></span></span><br><span class="line"><span class="keyword">using</span> <span class="keyword">namespace</span> <span class="built_in">std</span>;</span><br><span class="line"><span class="keyword">int</span> n,m,tot,sum,f[<span class="number">5001</span>];</span><br><span class="line"><span class="class"><span class="keyword">struct</span> <span class="title">node</span>{</span></span><br><span class="line"> <span class="keyword">int</span> u,v,c;</span><br><span class="line">}a[<span class="number">200010</span>];</span><br><span class="line"><span class="function"><span class="keyword">int</span> <span class="title">cmp</span><span class="params">(<span class="keyword">const</span> node &u,<span class="keyword">const</span> node &v)</span></span>{</span><br><span class="line"> <span class="keyword">return</span> u.c<v.c;</span><br><span class="line">}</span><br><span class="line"><span class="function"><span class="keyword">int</span> <span class="title">getf</span><span class="params">(<span class="keyword">int</span> u)</span></span>{</span><br><span class="line"> <span class="keyword">if</span>(f[u]==u)<span class="keyword">return</span> u;</span><br><span class="line"> <span class="keyword">return</span> f[u]=getf(f[u]);</span><br><span class="line">}</span><br><span class="line"><span class="function"><span class="keyword">int</span> <span class="title">main</span><span class="params">()</span></span>{</span><br><span class="line"> <span class="built_in">cin</span>>>n>>m;</span><br><span class="line"> <span class="keyword">if</span>(m<n<span class="number">-1</span>){<span class="built_in">cout</span><<<span class="string">"orz"</span><<<span class="built_in">endl</span>;<span class="keyword">return</span> <span class="number">0</span>;}</span><br><span class="line"> <span class="keyword">for</span>(<span class="keyword">int</span> i=<span class="number">1</span>;i<=m;i++)<span class="built_in">cin</span>>>a[i].u>>a[i].v>>a[i].c;</span><br><span class="line"> <span class="keyword">for</span>(<span class="keyword">int</span> i=<span class="number">1</span>;i<=n;i++)f[i]=i;</span><br><span class="line"> sort(a+<span class="number">1</span>,a+m+<span class="number">1</span>,cmp);</span><br><span class="line"> <span class="keyword">for</span>(<span class="keyword">int</span> i=<span class="number">1</span>;i<=m;i++){</span><br><span class="line"> <span class="keyword">int</span> fu=getf(a[i].u),fv=getf(a[i].v);</span><br><span class="line"> <span class="keyword">if</span>(fu!=fv){</span><br><span class="line"> f[fu]=fv;</span><br><span class="line"> sum++;</span><br><span class="line"> tot+=a[i].c;</span><br><span class="line"> }</span><br><span class="line"> <span class="keyword">if</span>(sum==n<span class="number">-1</span>)<span class="keyword">break</span>;</span><br><span class="line"> }</span><br><span class="line"> <span class="built_in">cout</span><<tot<<<span class="built_in">endl</span>;</span><br><span class="line">}</span><br></pre></td></tr></table></figure>
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