斐波那契数列-O(1) Posted on 2020-Mar-02 Edited on 2020-Mar-29 Views: Valine: 引自:《信息学奥赛之-数学一本通》 揍是这样: F(n)=55⋅[(1+5)n−(1−5)n]\operatorname{F}(n)=\dfrac{\sqrt{5}}{5}\cdot\left[\left(1+\sqrt{5}\right)^n-\left(1-\sqrt{5}\right)^n\right] F(n)=55⋅[(1+5)n−(1−5)n] 代码揍这么简单: 123int ferbo(int n){ return (sqrt(5)/5)*(pow((1+sqrt(5))/2,n)-pow((1-sqrt(5))/2,n));} 要是再加个快速幂就更棒了(够快了,懒得写) Post author: Alex Post link: https://schtonn.github.io/posts/ferbonacci/ Copyright Notice: All articles in this blog are licensed under BY-NC-SA unless stating additionally.